Given the area of the figure, find its perimeter to the nearest tenth.
1. A = 90 ft^2; number of squares: 6.
2. A baseball diamond is a square with an area of 8100 square feet. The length of the diagonal of any square is equal to √2 times it's side length. Finds fhe distance from home plate to second base (the length of the diagonal) to the nearest hundredth of a foot.
Answers:
1. The perimeter of the figure is 54. 2 ft.?
2. The length from home plate to second base is 127. 28 ft.?
You do not need me to operate the calculator Victoria :)
So my answers are correct?
To find the perimeter of the figure given the area, we need additional information about the shape of the figure. However, we can try to make some assumptions based on the given information.
For the first scenario, if the figure is made up of 6 squares and the area is 90 square feet, we can assume that all the squares are of the same size, resulting in each square having an area of 15 square feet (90 ft^2 / 6 squares).
To find the side length of one square, we can take the square root of the area: √15 ft ≈ 3.87 ft.
Since there are 6 squares in total, the total length of all the sides would be 6 times the side length of one square: 6 * 3.87 ft = 23.22 ft. Rounding to the nearest tenth, the perimeter of the figure is approximately 23.2 ft.
For the second scenario, we are given that the baseball diamond is a square with an area of 8100 square feet. To find the length from home plate to second base (the diagonal), we can use the formula for the diagonal of a square.
The formula states that the length of the diagonal (d) of a square is equal to the square root of 2 (√2) times its side length (s). Thus, we can set up the equation:
d = √2 * s
From the given information, we know the area of the square is 8100 sq ft. Since the square is a perfect square, its side length would also be a perfect square root. Taking the square root of 8100 gives us the side length:
s = √8100 ft ≈ 90 ft
Using this value for the side length, we can find the diagonal:
d = √2 * 90 ft ≈ 127.28 ft.
Rounding to the nearest hundredth of a foot, the distance from home plate to second base (the diagonal) is approximately 127.28 ft.
Please note that these calculations are based on certain assumptions about the shape of the figures mentioned in the given information. If more specific information or diagrams are provided, we might be able to provide more accurate and precise answers.