length of a rectangle exceeds its breadth by 4 m. if the parimeter of the the rectangle is 84 m, find its length and breadth.?
Perimeter formula = 2(l+b)
Length and breadth according to question=x,x+4
2(x+x+4)=84
2x+2x+8=84
4x+8=84
4x=84-8
4x=76
x=76รท4=19
Breadth=x=19
Lenght=x+4=23
Tq
length=23 and width=19
width: w
length: w+4
2(w + w+4) = 84
Now just solve for w and calculate w+4.
Breadth -19
Length-23
Math
To find the length and breadth of the rectangle, we can use the information given in the question. Let's assume the breadth of the rectangle is "b" meters.
According to the question, the length of the rectangle exceeds its breadth by 4 meters. So, the length can be represented as "b + 4" meters.
The perimeter of a rectangle is given by the formula: 2(length + breadth). In this case, the perimeter is 84 meters. So, we can set up the equation:
2(b + (b + 4)) = 84
Simplifying the equation:
2(2b + 4) = 84
4b + 8 = 84
4b = 76
b = 19
Now, we have found the value of "b" which represents the breadth of the rectangle.
To find the length, substitute the value of "b" back into the equation for the length:
Length = breadth + 4 = 19 + 4 = 23
Therefore, the length of the rectangle is 23 meters and the breadth is 19 meters.
2(x+x+4)
2x+2x+4
How is it possible?