The liquid bromoethane has a density of 1.46 g/mL at 20 °C. If a sample of this liquid at 20 °C has a volume of 59.9 mL, how many grams of liquid are there in the sample
mass (m) = density (ρ) * volume (v)
= 1.46 g/mL * 59.9 mL
= 87.5 g
To calculate the mass of the liquid, we can use the formula:
Mass = Density x Volume
Given that the density of liquid bromoethane is 1.46 g/mL and the volume of the sample is 59.9 mL, we can plug those values into the formula:
Mass = 1.46 g/mL x 59.9 mL
Calculating this expression gives us:
Mass = 87.454 g
Therefore, there are 87.454 grams of liquid bromoethane in the sample.
To determine the number of grams of liquid bromoethane in the given sample, we can use the formula:
Mass = Density x Volume
Given:
Density of bromoethane = 1.46 g/mL
Volume of the sample = 59.9 mL
Now, we can substitute these values into the formula to calculate the mass:
Mass = 1.46 g/mL x 59.9 mL
To find the answer, multiply the density by the volume:
Mass ≈ 87.554 g
Therefore, there are approximately 87.554 grams of liquid bromoethane in the sample.