Brandy plans to frame a picture with a sheet of construction paper. Her picture is 8 inches wide and 13 inches long. She wants the frame to extend 1 inch beyond the picture on all sides l. How wide and long should the frame be? What is the perimeter of her picture and of the frame?
8 + 2 = 10
13 + 2 = 15
The frame should be 10 by 15 inches.
P = 2L + 2W
Thank you so much.
You're very welcome.
To determine the dimensions of the frame, we need to add 1 inch to both the width and length of the picture.
The picture is 8 inches wide, and we need to add 1 inch on both sides. Therefore, the width of the frame should be 8 + 1 + 1 = 10 inches.
Similarly, the picture is 13 inches long, and we need to add 1 inch on both the top and bottom. Thus, the length of the frame should be 13 + 1 + 1 = 15 inches.
Now, let's calculate the perimeters of the picture and the frame.
The perimeter of a rectangle can be calculated by adding up all the sides.
For the picture:
Perimeter of the picture = 2 * (width + length)
= 2 * (8 + 13)
= 2 * 21
= 42 inches
For the frame, we can calculate the perimeter by adding up all the sides of the frame.
Perimeter of the frame = 2 * (width + length)
= 2 * (10 + 15)
= 2 * 25
= 50 inches
Therefore, the width and length of the frame should be 10 inches and 15 inches, respectively. The perimeter of the picture is 42 inches, and the perimeter of the frame is 50 inches.