A rectangle is twice as long as it is wide. Its perimeter is 60cm. find its length and width.
length=2w
2(w+2w) = 60
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A rectangle is 4times as long as it is wide and its perimeter is 80 centimeters find its demesions
To find the length and width of a rectangle, we can set up equations based on the given information.
Let's say the width of the rectangle is 'w' cm. According to the problem, the length is twice as long as the width, so the length would be '2w' cm.
The formula to calculate the perimeter of a rectangle is given by:
Perimeter = 2 * (Length + Width)
Substituting the given values:
60 = 2 * (2w + w)
Simplifying the equation:
60 = 2 * (3w)
60 = 6w
Divide both sides of the equation by 6 to solve for 'w':
w = 10
Now, we can substitute the value of 'w' back into the initial equation to find the length:
Length = 2w = 2 * 10 = 20
Therefore, the length of the rectangle is 20 cm, and the width is 10 cm.