Ethanol glycol has a density of 1.11 g/cm^3.
What is the volume in L of 4.1 kg of this liquid?
mass = volume x density or
volume = mass/density.
mass = 4100 g
density 1.11
Substitute and solve for volume (in mL) and convert to L.
4510
To find the volume of a substance, you can use the formula:
Volume = Mass / Density
Given:
Density of ethanol glycol = 1.11 g/cm^3
Mass of the liquid = 4.1 kg
First, we need to convert the mass from kilograms (kg) to grams (g) since the density is given in grams per cubic centimeter (g/cm^3).
1 kg = 1000 g
Therefore, the mass of the liquid in grams is:
4.1 kg * 1000 g/kg = 4100 g
Now we can substitute the values into the formula and calculate the volume:
Volume = 4100 g / 1.11 g/cm^3
Volume = 3693.69 cm^3
Since the volume is expressed in cm^3, we can convert it to liters by dividing by 1000 (since there are 1000 cm^3 in 1 L):
Volume = 3693.69 cm^3 / 1000 cm^3/L
Volume ≈ 3.69 L
Therefore, the volume of 4.1 kg of ethanol glycol is approximately 3.69 liters.