an engine pumps of 100 kg of water through a height of 10m in 5 second. Given that the efficiency of engine is 60%. If g=10m/s^2 the power of engine is
To calculate the power of the engine, we can use the formula:
Power = (Work done) / (Time taken)
First, let's calculate the work done by the engine:
Work done = Force x Distance
The force can be calculated using the equation:
Force = Mass x Acceleration
Given that the mass of the water pumped is 100 kg and the acceleration due to gravity is 10 m/s^2:
Force = 100 kg x 10 m/s^2
= 1000 N
Next, we need to calculate the distance over which the force is applied. In this case, it is the height the water is pumped, which is 10 m.
Distance = 10 m
Now we can substitute the values into the formula to calculate the work done:
Work done = 1000 N x 10 m
= 10000 J
Since the efficiency of the engine is given as 60%, we need to factor that in when calculating the power. Efficiency is defined as:
Efficiency = (Useful work output) / (Total work input)
Since we know the engine's efficiency and the total work input, we can calculate the useful work output:
Useful work output = Efficiency x Total work input
Total work input = Work done
Substituting the values:
Useful work output = 0.6 x 10000 J
= 6000 J
Finally, we can calculate the power:
Power = Useful work output / Time taken
Given that the time taken is 5 seconds:
Power = 6000 J / 5 s
= 1200 W
Therefore, the power of the engine is 1200 watts.
(A).3.3KW(B).0.33KW(C).3.3KW(D).3.3KW
5245485
Power
=mgh/Δt / efficiency
=100kg*10m/s²*10m/5s / 60%
= 2000/0.6
= 3333 W
= 3.33 KW
Thank you for posting the answers, but there are too many decimal points that I cannot make anything out of them. In addition, (C) and (D) seem identical to me.
POWER
= mgh/t/efficiency
= 100*10*10/5/60
= 2000/0.6
= 3333 w
= 3.33 kw