Find the force when two poles to strength 100 and 90 cgs units are placed at a distance to 20 cm a part.
This makes no sense to me.
6 dynes
To find the force between two poles, we can use Coulomb's Law. Coulomb's Law states that the force between two charged objects is directly proportional to the product of their charges and inversely proportional to the square of the distance between them.
The formula for Coulomb's Law is:
F = (k * Q1 * Q2) / r^2
Where:
F is the force between the poles
k is the Coulomb constant
Q1 and Q2 are the charges of the poles
r is the distance between the poles
First, let's convert the pole strengths from cgs units to SI units (Coulombs). We know that 1 cgs unit of charge is equal to 3.3356 x 10^-10 Coulombs. Hence:
Charge of pole 1 (Q1) = 100 cgs units * (3.3356 x 10^-10 Coulombs/cgs unit)
Charge of pole 1 (Q1) ≈ 3.3356 x 10^-8 Coulombs
Charge of pole 2 (Q2) = 90 cgs units * (3.3356 x 10^-10 Coulombs/cgs unit)
Charge of pole 2 (Q2) ≈ 3.002 x 10^-8 Coulombs
Next, let's convert the distance between the poles from centimeters to meters:
Distance (r) = 20 cm * (1 meter/100 cm)
Distance (r) = 0.2 meters
Now, we can substitute the values into the Coulomb's Law formula:
F = (k * Q1 * Q2) / r^2
The Coulomb constant (k) is approximately equal to 8.99 x 10^9 N m^2/C^2.
F = (8.99 x 10^9 N m^2/C^2) * (3.3356 x 10^-8 Coulombs) * (3.002 x 10^-8 Coulombs) / (0.2 meters)^2
Calculating this expression will give us the force between the poles.