If an arrow is shot upward on the moon with a velocity of 56 m/s, its height in meters after t seconds is given by . Find the instantaneous velocity after one second.
Please walk me through each step
Sorry forgot to give you the equation
its heigh in meters after t seconds is given by
h=56t-0.41t^2
Since you labeled it Calculus, ....
dh/dt =56 - .82t
when t = 1
dh/dt = 56 - .82(1)
=55.18 m/s
Thanks ur amaizing!
To find the instantaneous velocity after one second, we need to differentiate the equation for the height of the arrow with respect to time. The given equation for the height of the arrow is not provided in the question, so it is not possible to calculate the instantaneous velocity without it.
However, if the equation for the height of the arrow is provided, we can differentiate it using calculus to find the instantaneous velocity. The derivative of the equation with respect to time will give us the velocity as a function of time, which we can then evaluate at t=1 second to find the instantaneous velocity after one second.