What is the weight of a 4.82 kg backpack in Newton and the acceleration of the backpack if a net force of 10.0 N is applied in m/s2?
Wt. = m*g = 4.82kg * 9.8N/kg = 47.24 N.
a = F/m = 10/4.82
To find the weight of the backpack in Newton, we can use the formula:
Weight (in Newton) = mass (in kg) × acceleration due to gravity (in m/s^2)
The acceleration due to gravity on Earth is approximately 9.8 m/s^2.
So, the weight of the 4.82 kg backpack would be:
Weight = 4.82 kg × 9.8 m/s^2
To find the acceleration of the backpack when a net force of 10.0 N is applied, we can use Newton's second law of motion:
Net force (in N) = mass (in kg) × acceleration (in m/s^2)
Rearranging the formula, we get:
Acceleration = Net force / mass
So, the acceleration of the backpack would be:
Acceleration = 10.0 N / 4.82 kg
To find the weight of the backpack in Newton, we use the formula:
Weight (W) = mass (m) × acceleration due to gravity (g)
Assuming the acceleration due to gravity is 9.8 m/s², we can calculate the weight of the backpack:
W = 4.82 kg × 9.8 m/s²
W ≈ 47.236 N
Therefore, the weight of the 4.82 kg backpack is approximately 47.236 N.
Now, we can determine the acceleration of the backpack using Newton's second law:
Force (F) = mass (m) × acceleration (a)
Given that a net force of 10.0 N is applied, we can rearrange the formula to find the acceleration:
10.0 N = 4.82 kg × a
Dividing both sides of the equation by 4.82 kg, we get:
a = 10.0 N / 4.82 kg
a ≈ 2.07 m/s²
Therefore, the acceleration of the backpack, when a net force of 10.0 N is applied, is approximately 2.07 m/s².