Each crate moves from position 1, to position 2 to position 3. All of the crates are identical. the coordinate values given are in meters.
Rank A through F in order from least to greatest, on the basis of the displacement from the position 1. If any crates traveled the same displacement, put them next to the same number. Be careful because sometimes the conveyor belt reverses direction, making position 2 further to the right than position 3.
A) Position 1 = 0 m
position 2 = 3 m
position 3 = 6 m
B) position 1 = 5 m
Position 2 = 12 m
position 3 = 15 m
C) position 1 = -5 m
position 3 = 3 m
position 2 = 6 m
D) position 1 = 0 m
position 3 = 3 m
position 2 = 6 m
E) position 1 = -10 m
position 2 = 0 m
position 3 = 6 m
F) position 3 = 0 m
position 2 = 3 m
position 1 = 6 m
for this same table can you also find the distance.
for this part i found these numbers but not sure:
A) 6 m
B) 10 m
C) 14 m
D) 9 m
E) 16 m
F) 6 m
displacement is a vector. Without knowing how positions are located, it it cannot be determined. If they are in a straight line, then F should be -6,
D is wrong.
c is wrong.
I couldn't find the answers for displacement the answers i gave were for distance.
I am really confused about how to find them.
Thanks!
Miami Corporate & Wedding Events – Glenn Curtiss Historic Mansion
To rank the crates in order of displacement from position 1, we need to calculate the distance each crate has traveled. The displacement is the difference between the final position and the initial position. To calculate the distance, we need to consider the direction of the conveyor belt.
Let's go crate by crate:
A) The displacement is 6 meters (position 3 - position 1). We don't need to consider the direction as the conveyor belt does not reverse. Hence, the distance traveled is also 6 meters.
B) The displacement is 10 meters (position 3 - position 1). Again, as the conveyor belt does not reverse, the distance traveled is also 10 meters.
C) This one is a bit tricky because the positions are not given in sequential order. However, if we arrange the positions in order, we have position 1 = -5m, position 2 = 6m, and position 3 = 3m. Hence, the displacement is 3 meters (position 3 - position 1). The distance traveled is also 3 meters.
D) Similar to case C, we arrange the positions in order as position 1 = 0m, position 2 = 6m, and position 3 = 3m. The displacement is 3 meters (position 3 - position 1), and hence the distance traveled is 3 meters.
E) Here, the conveyor belt reverses direction, so we need to consider the distance traveled in both directions. The crate starts at position 1 = -10m, moves to position 2 = 0m, and then to position 3 = 6m. The displacement from position 1 to position 2 is 0 meters, and the displacement from position 2 to position 3 is 6 meters. Hence, the total displacement is 6 meters (0m + 6m). The distance traveled is also 6 meters.
F) In this case, the positions are given in reverse order. By rearranging them, we have position 1 = 6m, position 2 = 3m, and position 3 = 0m. The displacement is 0 meters (position 3 - position 1), and therefore the distance traveled is also 0 meters.
Ranking the crates from least to greatest based on displacement:
F (0 meters)
C (3 meters)
D (3 meters)
A (6 meters)
E (6 meters)
B (10 meters)
Calculating the distances:
F (0 meters)
C (3 meters)
D (3 meters)
A (6 meters)
E (6 meters)
B (10 meters)
So, based on displacement from position 1:
F, C, D, A, E, B
And based on distance traveled:
F, C, D, A, E, B
Please note that the values provided are based on the information given and may be subject to correction if any positional information is inaccurate or missing.