A line passes through the points (-10,-4) and(-1,2) .
What is the y-intercept of the line?
a)(0,8/3)
b)(8/3,0)
c)(0,-4)
d)(-4,0)
slope= changey/changex=(2-(-4))/(-1-(-10))
= 6/9
y= slope*x + Yintercept
using either pint (I will do the second)
2=6/9 * - 1 + Yintercept
Yintercept=8/3 which makes answer a the only possible answer.
check my work
To find the y-intercept of a line, we need to find the point where the line crosses the y-axis. The y-axis is the vertical axis in a coordinate plane, where the x-coordinate is always 0.
In this case, we are given two points that the line passes through: (-10,-4) and (-1,2).
To find the y-intercept, we need to find the point where the line crosses the y-axis, which means we need to find the point where the x-coordinate is 0.
Let's start with the equation of the line, which is in the form y = mx + b, where m is the slope of the line and b is the y-intercept.
First, let's find the slope of the line using the two given points. The slope formula is:
m = (y2 - y1) / (x2 - x1)
Using the two given points, (-10,-4) and (-1,2), we can plug in the values into the slope formula:
m = (2 - (-4)) / (-1 - (-10))
m = (2 + 4) / (-1 + 10)
m = 6 / 9
m = 2/3
Now that we have the slope, we can plug in the slope and one of the points into the equation y = mx + b to solve for b.
Using the point (-1,2), we have:
2 = (2/3)(-1) + b
2 = -2/3 + b
2 + 2/3 = b
6/3 + 2/3 = b
8/3 = b
So the y-intercept is (0, 8/3).
Therefore, the correct answer is (a) (0, 8/3).