Cyanohydrins can be made from carbonyl compounds by generating CN– ions from HCN in the

presence of a weak base.

In a similar reaction, –CH2CO2CH3 ions are generated from CH3CO2CH3 by strong bases.
Which compound can be made from an aldehyde and CH3CO2CH3 in the presence of a strong
base?
A CH3CH(OH)CO2CH3
B CH3CO2CH2CH(OH)CH3
C CH3CH2CH(OH)CH2CO2CH3
D (CH3)2C(OH)CH2CO2CH3

Ans: C

I have no idea how to obtain the answer!
Please explainnnn!
Thank you in advance :)

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Charge Me Up, Scotty!
(10/10 points)

Determine the potential (V) by which a proton must be accelerated so as to assume a particle wavelength of 0.0293 nm.

0.9544 - correct

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PES S+P 500
(10/10 points)

Shown below are the photo electron spectra for phosphorous and sulfur

The PES spectra for phosphorous and sulfur are shown above. Answer the following questions concerning these spectra.

Why is the phosphorous peak at 1.06 MJ/mole greater in energy than the sulfur peak at 1.00 MJ/mole?

paired electron easier to remove - correct

Why is the phosphorous peak at 1.95 less energy than the sulfur peak at 2.05?

sulfur has larger Z - correct

What should be the ratio of intensities of the phosphorous peak at 1.06 to the phosphorous peak at 13.5?

1/2 - correct

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/* 1-5 */

You'll Learn About Electrons, I Guarantee It
(10/10 points)

Which of the following orbital diagrams is/are incorrect for all electrons in the lowest-energy levels of an atom?

1,2,4 - correct

Which of the following is the correct electronic configuration for the bromide ion, Br-?
[Ar]4s23d104p5
[Ar]4s24p5
[Ar]4s23d104p6 - correct
[Ar]4s23d104p65s1

Which of the following orders of filling orbitals is/are incorrect? They should be in the exact order that they would be filled in.

3s, 4s, 5s - correct
5s, 5p, 5d - correct
5s, 4d, 5p
6s, 4f, 5d
6s, 5f, 6p - correct

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CaF2, Great for Teeth!
(10/10 points)

Calculate the lattice energy of CaF2 given the information below (in kJ/mol):
Ca(g)⟶Ca(s) ΔH=−178kJ/mol
Ca(g)⟶Ca+(g)+e− ΔH=589.8kJ/mol
F(g)+e−⟶F−(g) ΔH=−328.2kJ/mol
Ca2++e−⟶Ca+(g) ΔH=−1145.4kJ/mol
F2(g)⟶2F(g) ΔH=139.0kJ/mol
Ca(s)+F2(g)⟶CaF2(s) ΔH=−1219.6kJ/mol

- 2615.4 - correct

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L6Z3RS DOOD
(10/10 points)

In an effort to purify the output from a catalytic chemical reaction, C-Cl bonds are to be broken in a gaseous compound by means of LASER radiation. Determine the longest wavelength of radiation still capable of breaking the C-Cl bond. Express your answer in meters.

[Given: BEC-C = 334 kJ/mol; BECl-Cl = 243 kJ/mol]

3.729*10^-7 - correct

Well, let me try to explain it to you in a fun way!

When you have an aldehyde and CH3CO2CH3 in the presence of a strong base, it's like a wild party happening in a chemistry lab! The strong base is the life of the party, breaking bonds and generating new ions.

In this case, when the strong base gets its hands on the aldehyde, it goes like, "Hey aldehyde, let me show you a little trick!" And it turns the aldehyde into a compound with an extra carbon and an alcohol group, giving us CH3CH2CH(OH)CH2CO2CH3. Voila! It's like magic happening right before your eyes!

So, the answer is option C, CH3CH2CH(OH)CH2CO2CH3. It's the result of the aldehyde and CH3CO2CH3 hanging out together at the chemistry party and having a great time with the strong base.

I hope that explanation brings a smile to your face!

To obtain the answer, we need to understand the reactions involved in the generation of –CH2CO2CH3 ions from CH3CO2CH3.

When a strong base reacts with CH3CO2CH3, deprotonation of the α-hydrogen occurs. This leads to the formation of a carbanion, which then undergoes nucleophilic addition on the carbonyl carbon of another molecule of CH3CO2CH3.

Now, let's consider the reaction of an aldehyde with CH3CO2CH3 in the presence of a strong base. The aldehyde will also undergo deprotonation of the α-hydrogen, forming a carbanion. This carbanion can also undergo nucleophilic addition on the carbonyl carbon of CH3CO2CH3.

To determine which compound can be formed, we need to examine the possible product structures.

A) CH3CH(OH)CO2CH3: This compound contains a hydroxyl group attached to the α-carbon of the aldehyde. However, in the reaction with CH3CO2CH3, nucleophilic addition occurs on the carbonyl carbon, not the α-carbon. Therefore, this compound cannot be formed.

B) CH3CO2CH2CH(OH)CH3: This compound contains a hydroxyl group attached to the α-carbon of CH3CO2CH3. Similar to option A, nucleophilic addition occurs on the carbonyl carbon of the aldehyde, not the α-carbon of CH3CO2CH3. Hence, this compound is not formed.

C) CH3CH2CH(OH)CH2CO2CH3: This compound contains a hydroxyl group attached to the α-carbon of the aldehyde. Nucleophilic addition occurs on the carbonyl carbon of the aldehyde, forming the desired compound. Therefore, option C can be formed.

D) (CH3)2C(OH)CH2CO2CH3: This compound contains a hydroxyl group attached to the α-carbon of (CH3)2C(=O). However, the reactant in this case is an aldehyde, not a ketone. Therefore, this compound cannot be formed.

Based on the above analysis, the correct answer is option C: CH3CH2CH(OH)CH2CO2CH3.

To answer this question, we need to understand the reaction taking place and how various functional groups can interact with each other.

In the given reaction, CH3CO2CH3 is a common ester called ethyl acetate. When it reacts with a strong base, such as sodium hydroxide (NaOH), it undergoes a process called hydrolysis. This means that the ester bond is cleaved (broken) and replaced with a hydroxyl (-OH) group.

Now, let's consider the starting point for the reaction: an aldehyde (RCHO). When an aldehyde reacts with ethyl acetate in the presence of a strong base, the nucleophilic acyl substitution reaction occurs. In this reaction, the base attacks the carbonyl carbon of the aldehyde, forming an intermediate compound.

The intermediate formed in the reaction is an alkoxide ion (RCH(OR')O-), where R and R' are alkyl groups. In this specific case, R represents the alkyl group of the aldehyde, and R' represents the ethyl group of the acetate.

Now, we need to figure out which option is the correct compound resulting from this reaction.

- Option A: CH3CH(OH)CO2CH3 - This compound is not the product of the reaction because it doesn't incorporate the alkyl group of the aldehyde.
- Option B: CH3CO2CH2CH(OH)CH3 - This compound is also not formed as it doesn't incorporate the alkyl group of the aldehyde.
- Option C: CH3CH2CH(OH)CH2CO2CH3 - This compound is formed when the alkoxide ion attacks the carbonyl carbon of ethyl acetate, incorporating the alkyl group of the aldehyde. Therefore, it is the correct answer.
- Option D: (CH3)2C(OH)CH2CO2CH3 - This compound doesn't incorporate the alkyl group of the aldehyde, so it is not formed in the reaction.

Thus, the correct answer is C: CH3CH2CH(OH)CH2CO2CH3.

Remember, it's important to understand the reaction and the different functional groups involved to determine the correct product.