A cylindrical gasoline tank is 50 ft high and has diameter 70 ft.
How many gallons of gasoline will the tank hold if there are 7.5 gallons in 1 ft3 ?
area of base = pi r^2 = 35^2 pi
volume = height*base area = 50 * 35^2 pi ft^3
gallons = 50 * 35^2 * pi * 7.5
A cylindrical gasoline tank is 50 ft high and has diameter 70 ft.
How many gallons of gasoline will the tank hold if there are 7.5 gallons in 1 ft3 ?
How many gallons of gasoline will the tank hold if there are 7.5 gallons in 1 ft3 ?
To find the number of gallons of gasoline the tank will hold, we need to calculate the volume of the tank in cubic feet and then convert it to gallons using the given conversion factor.
First, let's find the volume of the cylindrical tank using the formula for the volume of a cylinder:
Volume = π * r^2 * h
where π is a mathematical constant (approximately 3.14159), r is the radius of the cylinder, and h is the height of the cylinder.
Given that the diameter of the tank is 70 ft, we can calculate the radius as half the diameter: r = 70 ft / 2 = 35 ft.
Using the given height of 50 ft and the radius of 35 ft, we can now calculate the volume:
Volume = 3.14159 * (35 ft)^2 * 50 ft
≈ 3.14159 * 1225 ft^2 * 50 ft
≈ 192625 * 50 ft^3
≈ 9,631,250 ft^3
Next, we need to convert the volume from cubic feet to gallons. We know that there are 7.5 gallons in 1 cubic foot, so we can multiply the volume by the conversion factor:
Gallons = Volume * 7.5
≈ 9,631,250 ft^3 * 7.5 gallons/ft^3
≈ 72,234,375 gallons
Therefore, the cylindrical gasoline tank will hold approximately 72,234,375 gallons of gasoline.