# Chemistry

The piperazine content of an impure commercial material can be determined by precipitating and weighing the diacetate:

(C2H4)2N2H2 + 2 CH3COOH → (C2H4)2N2H2(CH3COOH)2

In one experiment, 0.3126 gram of the sample was dissolved in 25 mL of acetone, and 1 mL of acetic acid was added. After 5 minutes, the precipitate was filtered, washed with acetone, dried at 110 °C and found to weigh 0.7121 gram. What is the weight percent of piperazine in the commercial material?

I know mass percent = (mass solute)/(mass solution) *100

But in this case, im am not knowing how to calculate the mass of solution

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1. You know mass ppt is 0.7121g and that is the piperazine diacetate (pipd). Calculate the molar mass of ppd. Then calculate the molar mass of the piperzine (pip). Convert 0.7121g pipd to g pip this way.
0.7121g x (molar mass pip/molar mass pipd)
Then mass% = (mass pip/mass sample)*100 and %pip = (mass pip/0.3126)*100 = ?

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