Sally rolls a fair number cube 8 times and gets a 5 twice. What is the experimental probability that on her next roll, she will roll a 5?
I know that experimental probability is f/n, so the number of trials is now 9, but is the number of times Sally roll a 5 two times or three?
The 1st thing you would do is figure the percent of a 5 coming up from the first 8 rolls Sally did.
5/8 = 25%
The chance that she would roll a 5 on the 9th attempt is 25%
But, we know that the 5 came up two times in the first eight rolls.
To find the experimental probability of rolling a 5 on Sally's next roll, we need to know the number of times Sally rolls a 5 in the total number of trials.
In this case, Sally rolled the number cube 8 times and obtained a 5 twice. Therefore, the number of times Sally rolled a 5 is two.
Since we want to calculate the probability for the next roll, the total number of trials will be nine, as you correctly mentioned.
So, using the formula for experimental probability, which is the number of favorable outcomes (rolling a 5) divided by the total number of outcomes (number of trials), we have:
Experimental probability = Number of times Sally rolled a 5 / Total number of trials
= 2 / 9
Hence, the experimental probability that Sally will roll a 5 on her next roll is 2/9.