The figure below shows an electron passing between two charged metal plates that create an 115 N/C vertical electric field perpendicular to the electron’s original horizontal velocity. (These can be used to change the electron’s direction, such as in an oscilloscope.) The initial speed of the electron is 3.30×106 m/s, and the horizontal distance it travels in the uniform field is 4.10 cm. What is its vertical deflection?

If two equal charges each of 1.0 C each are separated in air by a distance of 1.0 km, what is the magnitude of the force acting between them? You will see that even at a distance as large as 1.0 km, the repulsive force is substantial because 1.0 C is a very significant amount of charge.

On the second question, this is coulombs law. I don't understand what your question is, or what you don't understand about it.

On the first, Force=qE
then find the time it is in the field
time=distancetraveled/velocity

Now you have the force, and time in the force,
distance=1/2 (force/mass)time^2

To find the vertical deflection of the electron, we first need to determine the time it takes for the electron to travel the horizontal distance in the uniform field.

We can use the formula:
Horizontal distance = (initial velocity * time) + (0.5 * acceleration * time^2)

Given:
Initial velocity (v) = 3.30 × 10^6 m/s
Horizontal distance (d) = 4.10 cm = 0.041 m
Acceleration (a) = 0 (since the electron is not accelerating horizontally)

Substituting the values into the equation, we have:
0.041 = (3.30 × 10^6 * t) + (0.5 * 0 * t^2)
0.041 = 3.30 × 10^6 * t

Solving for t:
t = 0.041 / (3.30 × 10^6)
t ≈ 1.24 × 10^-8 seconds

Now, we can find the vertical deflection using the formula:
Vertical deflection = (vertical acceleration * time^2) / 2

Given:
Vertical acceleration (g) = 115 N/C (electric field)

Substituting the values into the equation, we have:
Vertical deflection = (115 * (1.24 × 10^-8)^2) / 2
Vertical deflection ≈ 8.62 × 10^-15 meters

Therefore, the vertical deflection of the electron is approximately 8.62 × 10^-15 meters.

To determine the vertical deflection of the electron, we can use the following steps:

1. Calculate the time it takes for the electron to traverse the horizontal distance in the uniform electric field.
- We can use the formula: time = distance / speed
- Given that the horizontal distance is 4.10 cm (or 0.0410 m) and the initial speed of the electron is 3.30×10^6 m/s, we can calculate the time: time = 0.0410 m / 3.30×10^6 m/s.

2. Determine the vertical displacement of the electron during that time.
- Since the electric field is perpendicular to the initial horizontal velocity of the electron, the electron will experience a constant vertical acceleration.
- We can use the formula: vertical displacement = 0.5 * acceleration * time^2
- The acceleration of the electron can be calculated using the formula: acceleration = electric field strength * charge of the electron / mass of the electron.
- The electric field strength is given as 115 N/C, the charge of the electron is a fundamental constant (-1.6 x 10^-19 C), and the mass of the electron is a fundamental constant (9.11 x 10^-31 kg).
- Substitute the values into the formula to calculate the acceleration.
- Once we have the acceleration and the time, we can plug them into the formula to calculate the vertical displacement.

3. Finally, calculate the vertical deflection.
- The vertical deflection is simply the vertical displacement of the electron.

By performing these calculations, you will be able to determine the vertical deflection of the electron.