A beam of unknow charged particles passes at right angles to the direction of magnetic field of 9.0 x 10^-2 T. if the speed of the particles is 3.0 x 10^4 m/s and the force experiences by a particle is 8.64 x 10^-16 N. How many electric charges are carried by one particle?
Use F = q V B to solve for the charge, q, in Coulombs.
F is the force (N) B the magnetic field (Tesla) and V is the velocity (m/s).
If they mean how many ELECTRONS (positive or negative) the particle's charge corresponds to, divide q by the electron charge, e. That will give you the number of extra or missing electrons.
I solved and got 3.2 x 10^-19 Coulombs.
What value do I divide that by?
The electron charge, e. You should know it.
http://en.wikipedia.org/wiki/Electron
It looks like you have two electrons.
To find the number of electric charges carried by one particle, we can make use of the equation for the force experienced by a charged particle moving perpendicular to a magnetic field:
F = q * v * B
where:
F is the force experienced by the particle,
q is the electric charge of the particle,
v is the velocity of the particle, and
B is the magnetic field strength.
We are given:
F = 8.64 x 10^-16 N,
v = 3.0 x 10^4 m/s,
and B = 9.0 x 10^-2 T.
We can rearrange the equation to solve for q:
q = F / (v * B)
Substituting the given values:
q = (8.64 x 10^-16 N) / ((3.0 x 10^4 m/s) * (9.0 x 10^-2 T))
Now, let's calculate the value of q.