Mandy can get 100kg of corn cob for $160 from Matt,on condition that she buys at least 100kg.From another supplier,she can buy 100kg or less for $1/cob,or more than 100kg for $0.60/cob.she gets $5/kg of con cobs or $1.25 for an individual con cob.if she sell over 100kg today.what is the best profit per cob she can make? The answer is $0.85,but I cannot work out,can someone please explain,thanks
Hmmm. you are mixing up price per kg and per cob, with no indication of how many cobs per kg.
To determine the best profit per cob, we need to compare the cost and selling price for each option. Let's break it down step by step:
1. Buying from Matt:
- Mandy can buy 100kg of corn cobs for $160.
- This means the cost per cob is $160/100kg = $1.60/cob.
2. Buying from the other supplier:
- If Mandy buys exactly 100kg, she can get each cob for $1.
- If she buys more than 100kg, she can get each cob for $0.60.
Now, let's calculate the selling price per cob:
- Mandy sells over 100kg at $5/kg, which means the selling price per cob is $5.
- If we compare this with the buying prices, we find:
- The buying price from Matt is $1.60/cob, and the selling price is $5/cob.
- The buying price from the other supplier is $1/cob (for 100kg) or $0.60/cob (for over 100kg), and the selling price is $5/cob.
From here, we can see that the selling price remains constant at $5 per cob regardless of the buying price.
Therefore, the best profit per cob Mandy can make is the difference between the selling price and the buying price. Let's compare the two options:
- If Mandy buys from Matt at $1.60/cob, her profit per cob would be $5 - $1.60 = $3.40.
- If she buys from the other supplier at $1/cob (for 100kg), her profit per cob would be $5 - $1 = $4.
- If she buys from the other supplier at $0.60/cob (for over 100kg), her profit per cob would be $5 - $0.60 = $4.40.
Therefore, the best profit per cob Mandy can make is $4.40, not $0.85.
If you were given a different answer, there may have been a calculation error or misunderstanding related to the question.