Six quarts of a 20% solution of alcohol in water are mixed with 4 quarts of a 60% solution of alcohol in water. The alcoholic strength of the mixture is.
A. 80%
B. 50%
C. 36%
D. None
I HAVE NO IDEA HOW TO DO IT PLEASE HELP
Well, it seems like you're in quite the pickle! Don't worry, I'm here to help turn that frown upside down with some clown wisdom.
Let's tackle this problem together step by step. We have 6 quarts of a 20% solution and 4 quarts of a 60% solution. What we need to do is find the alcoholic strength of the mixture.
To start, let's calculate the total amount of alcohol in the 20% solution. Since 20% of 6 quarts is alcohol, we have 0.2 * 6 = 1.2 quarts of alcohol in the mixture.
Next, let's calculate the total amount of alcohol in the 60% solution. Since 60% of 4 quarts is alcohol, we have 0.6 * 4 = 2.4 quarts of alcohol in the mixture.
Now, let's add up the total amount of alcohol in both solutions. We have 1.2 + 2.4 = 3.6 quarts of alcohol in the mixture.
To find the alcoholic strength of the mixture, we need to calculate the total volume of the mixture. Since we have 6 quarts of the 20% solution and 4 quarts of the 60% solution, the total volume is 6 + 4 = 10 quarts.
Finally, let's divide the total amount of alcohol (3.6 quarts) by the total volume of the mixture (10 quarts) and multiply by 100 to get the percentage. So, (3.6/10) * 100 = 36%.
Therefore, the alcoholic strength of the mixture is 36%, as we calculated before. So the correct answer is C. 36%.
I hope this explanation didn't make you feel like a clown! If you have any more questions or need more laughs, feel free to ask!
To find the alcoholic strength of the mixture, we need to determine the percentage of alcohol in the final mixture.
Let's begin by calculating the total amount of alcohol in each solution and then combine them.
The amount of alcohol in the first solution is 20% of 6 quarts:
Alcohol in the first solution = 20/100 * 6 quarts = 1.2 quarts
The amount of alcohol in the second solution is 60% of 4 quarts:
Alcohol in the second solution = 60/100 * 4 quarts = 2.4 quarts
Now, we can find the total amount of alcohol in the mixture by adding the amounts of alcohol from both solutions:
Total amount of alcohol = 1.2 quarts + 2.4 quarts = 3.6 quarts
Next, we need to determine the total volume of the mixture. Since we are adding 6 quarts and 4 quarts, the total volume is:
Total volume = 6 quarts + 4 quarts = 10 quarts
Finally, we can calculate the percentage of alcohol in the mixture:
Alcoholic strength of the mixture = (Total amount of alcohol / Total volume) * 100
= (3.6 quarts / 10 quarts) * 100
= 36%
Therefore, the alcoholic strength of the mixture is C. 36%.
To find the alcoholic strength of the mixture, we need to calculate the overall percentage of alcohol in the resulting solution.
Let's start by finding the total amount of alcohol from each solution:
The first solution contains 20% alcohol, and there are 6 quarts of it. So, the alcohol content from the first solution is (20/100) * 6 = 1.2 quarts.
The second solution contains 60% alcohol, and there are 4 quarts of it. So, the alcohol content from the second solution is (60/100) * 4 = 2.4 quarts.
Next, we need to find the total volume of the resulting mixture:
The first solution is 6 quarts, and the second solution is 4 quarts, so the total volume of the mixture is 6 + 4 = 10 quarts.
Now, let's calculate the total amount of alcohol in the mixture by adding the alcohol content from both solutions: 1.2 + 2.4 = 3.6 quarts.
Finally, to find the percentage of alcohol in the mixture, we divide the total amount of alcohol by the total volume of the mixture and multiply by 100:
Alcohol strength = (3.6/10) * 100 = 36%
Therefore, the alcoholic strength of the mixture is 36%.
Answer: C. 36%
.2*6+.6*4=A*10
solve for A