i'm a four digit number having all the digits odd except 9 and the digits are in ascending order. who am i?

To determine the four-digit number that meets the given conditions, we can start by considering the odd digits in ascending order: 1, 3, 5, 7, 9.

Since the number cannot contain the digit 9, let's exclude it from our possibilities.

Next, we arrange the remaining digits in ascending order: 1, 3, 5, 7.

The only four-digit number that satisfies all the given conditions is 1357.

Therefore, the number you are referring to is 1357.

To find the number, we can start by listing all the possible four-digit numbers that satisfy the given conditions.

First, we note that the digits must be in ascending order, which means the units digit is the smallest and the thousands digit is the largest. Since all the digits except 9 must be odd, there are three possible odd digits to choose from: 1, 3, and 5.

Let's consider the thousands digit first. It cannot be 9, so it must be one of the odd digits. Since the digits are in ascending order, and we have only three options, the thousands digit can only be 1.

Next, let's consider the hundreds digit. It must be greater than the previous digit (1), odd, and not 9. We have two options left: 3 and 5. Since the digits are in ascending order, the hundreds digit can only be 3.

Now, we move on to the tens digit. It also must be greater than the previous digit (3), odd, and not 9. We have one option left, which is 5.

For the units digit, it must be odd but not 9. The only option left is 7.

Putting all the digits together, the four-digit number that satisfies the given conditions is 1357.

So, the answer is 1357.

"..having all the digits odd except 9.."

but 9 is odd

Typo?