the sum of the digit of a two digit number is 13 and the diffrence btween the number and that form by reversing the digit is 27, find the number...
in the original number let the unit digit by x and the tens digit be y
the number is 10y+x
x+y = 13
then the number reversed is 10x + y
10x + y - (10y + x) = 27
9x - 9y = 27
x-y = 3
add the two equations:
2x = 16
x = 8
then y = 13-8 = 5
the number is 58
check:
85-58 = 27 ,
all is good