How many grams are there in 2.5 moles of CuSO4.5H2O?
grams = mols x molar mass
To determine the number of grams in 2.5 moles of CuSO4.5H2O, we need to use the molar mass of the compound. The molar mass is the sum of the atomic masses of each element in the compound, taking into account their respective subscripts.
Let's break down the compound CuSO4.5H2O:
- CuSO4: Copper sulfate formula unit (1 mole)
- 5H2O: Water molecules (5 moles)
First, we calculate the molar mass of CuSO4:
- Copper (Cu) has an atomic mass of 63.55 g/mol.
- Sulfur (S) has an atomic mass of 32.07 g/mol.
- Oxygen (O) has an atomic mass of 16.00 g/mol.
Adding them together:
(63.55 g/mol) + (32.07 g/mol) + 4 * (16.00 g/mol) = 159.61 g/mol
Now, let's calculate the molar mass of 5H2O:
- Hydrogen (H) has an atomic mass of 1.01 g/mol.
- Oxygen (O) has an atomic mass of 16.00 g/mol.
Adding them together:
10 * (1.01 g/mol) + 5 * (16.00 g/mol) = 90.10 g/mol
The molar mass of CuSO4.5H2O is the sum of the molar masses calculated above:
159.61 g/mol + 90.10 g/mol = 249.71 g/mol
Finally, to find the number of grams in 2.5 moles of CuSO4.5H2O, we multiply the number of moles by the molar mass:
2.5 moles * 249.71 g/mol = 624.28 grams
Therefore, there are approximately 624.28 grams in 2.5 moles of CuSO4.5H2O.