a ball dropped from rest bag by a little boy from window of a three storey apartment how far has it fallen fter 3s What is the ball's velocity after 4 second of fall How far does ball fall during the lst 4 second?
I have done several, your turn.
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To answer your questions step-by-step:
1. To determine how far the ball has fallen after 3 seconds, we can use the equation for the distance traveled during free fall:
distance = (1/2) * g * t^2
Where "g" is the acceleration due to gravity (approximately 9.8 m/s^2) and "t" is the time.
Plugging in the values, we get:
distance = (1/2) * 9.8 * 3^2
distance = (1/2) * 9.8 * 9
distance = 44.1 meters
Therefore, the ball has fallen approximately 44.1 meters after 3 seconds.
2. To find the ball's velocity after 4 seconds of fall, we can use the equation for velocity during free fall:
velocity = g * t
Plugging in the values, we get:
velocity = 9.8 * 4
velocity = 39.2 m/s
Therefore, the ball's velocity after 4 seconds of fall is 39.2 m/s.
3. To determine how far the ball falls during the last 4 seconds, we can subtract the distance covered during the first 3 seconds from the distance covered during the first 4 seconds.
The distance covered during the first 3 seconds is 44.1 meters (calculated above).
Using the same formula for distance during free fall, we can calculate the distance covered during the first 4 seconds.
distance = (1/2) * 9.8 * 4^2
distance = (1/2) * 9.8 * 16
distance = 78.4 meters
Therefore, the ball falls approximately 78.4 - 44.1 = 34.3 meters during the last 4 seconds.
To determine the distance fallen by a ball in free fall, we can use the equation:
distance (d) = 0.5 * acceleration (a) * time squared (t^2)
For objects in free fall near the Earth's surface, the acceleration due to gravity is approximately 9.8 m/s^2.
1. To find out how far the ball has fallen after 3 seconds, we can substitute the given values into the formula:
d = 0.5 * 9.8 * 3^2
= 0.5 * 9.8 * 9
= 44.1 meters
Therefore, the ball has fallen 44.1 meters after 3 seconds.
2. To determine the velocity of the ball after 4 seconds of falling, we can use another equation:
velocity (v) = acceleration (a) * time (t)
v = 9.8 * 4
= 39.2 m/s
The ball's velocity after 4 seconds of falling is 39.2 m/s.
3. To find out how far the ball falls during the last 4 seconds, we need to calculate the distance fallen between 0 and 4 seconds and subtract the distance fallen between 0 and 3 seconds.
For the first 4 seconds:
d1 = 0.5 * 9.8 * 4^2
= 0.5 * 9.8 * 16
= 78.4 meters
For the first 3 seconds:
d2 = 0.5 * 9.8 * 3^2
= 0.5 * 9.8 * 9
= 44.1 meters
Therefore, the distance fallen during the last 4 seconds is:
d1 - d2 = 78.4 - 44.1
= 34.3 meters
Hence, the ball falls 34.3 meters during the last 4 seconds.