In a list of numbers that starts with the number 13, every number is 4 less than twice the number that comes just before it.What will the fifth number in the list be?
(13 * 2) - 4 = 22
(22 * 2) - 4 = 40
Take it from there.
I know that, 22, 40, 76, 148, 292
the fifth is 292
but the answer is 1.18 2.40 3.76 4.148 5.196
may i ask is it include 13, if include 13, the answer is 148
Yes. The fifth number is 148.
To find the fifth number in the list, we need to follow the given pattern and calculate each number step by step.
According to the given information, each number in the list is 4 less than twice the number that comes just before it. Let's denote the numbers in the list as n1, n2, n3, n4, and n5.
Let's start by finding the second number, n2. The problem states that every number is 4 less than twice the number that comes just before it. So, we can write the equation for n2 as:
n2 = 2 * n1 - 4
Since the first number is given as 13, we can substitute n1 with 13 in the equation:
n2 = 2 * 13 - 4
n2 = 26 - 4
n2 = 22
Now, let's proceed to find the third number, n3. Using the same pattern, we have:
n3 = 2 * n2 - 4
Substituting the value of n2 we found earlier:
n3 = 2 * 22 - 4
n3 = 44 - 4
n3 = 40
Continuing similarly, we can find the fourth number, n4:
n4 = 2 * n3 - 4
Substituting the value of n3, we get:
n4 = 2 * 40 - 4
n4 = 80 - 4
n4 = 76
Finally, to find the fifth number, n5, we can apply the same pattern:
n5 = 2 * n4 - 4
Substituting the value of n4, we have:
n5 = 2 * 76 - 4
n5 = 152 - 4
n5 = 148
Therefore, the fifth number in the list will be 148.