A stone is projected vertically upwards with a velocity 10m/s .Find the maximum height reached by the body (g=10m/sec)
h = (V^2-Vo^2)/2g
h = (0-(10^2)/-20 = 5.0 m.
Why did the stone go see a doctor? Because it felt a little "up-tight"!
But seriously, let's calculate the maximum height reached by the stone. We can use the kinematic equation:
v² = u² + 2as
where:
v = final velocity (0 m/s at the highest point),
u = initial velocity (10 m/s),
a = acceleration due to gravity (-10 m/s², as it is directed downwards),
and s = displacement (we need to find this).
Rearranging the equation, we have:
s = (v² - u²) / (2a)
Substituting the values, we get:
s = (0² - 10²) / (2 * -10)
s = (-100) / (-20)
s = 5 meters
So, the maximum height reached by the stone is 5 meters. Just make sure not to stand beneath it when it comes back down!
To find the maximum height reached by the stone, we need to use the equation of motion for vertical motion. The equation is as follows:
v^2 = u^2 - 2g(h - h0)
where:
v = final velocity (when the stone reaches its highest point, the velocity will be 0)
u = initial velocity (10 m/s in this case)
g = acceleration due to gravity (10 m/s^2 in this case)
h = final height (the maximum height we're trying to find)
h0 = initial height (assuming the stone is projected from the ground, h0 = 0)
Plugging in the values, we can rearrange the equation to solve for h:
0^2 = (10 m/s)^2 - 2 * 10 m/s^2 * (h - 0)
0 = 100 m^2/s^2 - 20 m/s^2 * h
20 m/s^2 * h = 100 m^2/s^2
h = 100 m^2/s^2 / 20 m/s^2
h = 5 meters
Therefore, the maximum height reached by the stone is 5 meters.
To find the maximum height reached by the stone, we can use the equations of motion.
First, let's define the variables:
- Initial velocity (u) = 10 m/s (upwards)
- Acceleration due to gravity (g) = -10 m/s^2 (negative because it acts in the opposite direction of motion)
- Final velocity (v) = 0 m/s (at the highest point, the velocity becomes zero)
- Maximum height (h) = ?
The equation of motion for vertical motion is:
v^2 = u^2 + 2as
where v is the final velocity, u is the initial velocity, a is the acceleration, and s is the displacement (in this case, the maximum height).
To find the maximum height, we need to solve for s.
Substituting the given values into the equation:
0^2 = 10^2 + 2 * (-10) * s
Simplifying the equation:
0 = 100 - 20s
Rearranging the equation:
20s = 100
s = 100 / 20
s = 5 meters
Therefore, the maximum height reached by the stone is 5 meters.