*Cement is 70% CaO by mass
*Concrete is 17% cement by mass
*Concrete masses 150lbs. per cubic feet
*There are 27 cubic feet in a cubic yard
*15 cubic yards required for house of concrete.
CaCo3(s)---CaO(s)+CO2(g)
1.) How many kg. of carbon dioxide were liberated to make your foundation?
2.)How many kg. of limestone were consumed?
To find the answers to these questions, we need to follow a step-by-step approach using the information provided.
Step 1: Calculate the mass of cement in the concrete.
Given that the concrete is 17% cement by mass and there are 150 lbs. per cubic foot, we can calculate the mass of cement in one cubic yard of concrete.
Mass of cement in one cubic yard of concrete = (17/100) * (1 cubic yard) * (150 lbs./cubic foot) * (27 cubic feet / 1 cubic yard)
Note: We convert the percentage to a decimal by dividing by 100.
Step 2: Calculate the mass of CaO in the cement.
Given that cement is 70% CaO by mass, we can calculate the mass of CaO in one cubic yard of concrete.
Mass of CaO in one cubic yard of concrete = (70/100) * (Mass of cement in one cubic yard of concrete)
Step 3: Calculate the number of kg of carbon dioxide liberated.
According to the balanced chemical equation, 1 mole of CaO produces 1 mole of CO2. Therefore, the molar mass of CO2 is the same as the molar mass of CaO.
Molar mass of CO2 = Molar mass of CaO = 56.08 g/mol
Now, we can convert the mass of CaO into moles and then into kilograms of CO2 using the molar mass.
Number of moles of CaO = Mass of CaO in one cubic yard of concrete / Molar mass of CaO
Number of kg of CO2 liberated = Number of moles of CaO * Molar mass of CO2
Step 4: Calculate the mass of limestone consumed.
According to the balanced chemical equation, 1 mole of CaCO3 produces 1 mole of CaO. Therefore, the molar mass of CaCO3 is double the molar mass of CaO.
Molar mass of CaCO3 = 2 * Molar mass of CaO
Now, we can convert the mass of CaO into moles of CaCO3 and then into kilograms using the molar mass.
Number of moles of CaCO3 = Mass of CaO in one cubic yard of concrete / Molar mass of CaO
Number of kg of limestone consumed = Number of moles of CaCO3 * Molar mass of CaCO3
By following these steps, we can find the answers to the questions.