a particuler moves along the sides AB,BC,CD of a square of side 25m with a speed of 15m/s. Its average velocity is?

moved along three sides of square?

say 25 m east, 25/15 s
then 25 m north, 25/15 s
then 25 m west, 25/15 s
so displacement is 25 m north in 75/15 s

25 * 15/75 = 15/3 = 5 m/s north

To find the average velocity, we need to determine the total displacement and the total time taken.

The particle is moving along the sides AB, BC, CD of a square of side 25m.

The total displacement is the straight-line distance between the initial and final positions. In this case, as the particle moves along the sides of the square, the displacement is equal to the length of one side of the square, i.e., 25m.

Next, we need to calculate the total time taken.

The particle moves along each side of the square at a speed of 15m/s. The length of each side is 25m. So, the time taken to cover each side can be calculated using the formula: Time = Distance / Speed.

Time taken to cover AB = 25m / 15m/s = 5/3 seconds
Time taken to cover BC = 25m / 15m/s = 5/3 seconds
Time taken to cover CD = 25m / 15m/s = 5/3 seconds

To find the total time taken, we add up the time taken for each side:
Total time taken = (5/3 seconds) + (5/3 seconds) + (5/3 seconds) = 5 seconds.

Now that we have the total displacement (25m) and the total time taken (5 seconds), we can calculate the average velocity using the formula: Average Velocity = Total Displacement / Total Time taken.

Average Velocity = 25m / 5s = 5m/s

Therefore, the average velocity of the particle is 5m/s.