calculate the amount of heat energy required to melt a 1kg iron ingot initially at 20 ¡ãC? (heat of fusion for Fe is 33.0 J/g
You also need specific heat of iron and melting point
Watch your units, grams or kg , Joules or calories
to get up to Tmelt
heat = 1000 g * specific heat iron in Joules/gram deg C *(Tm-20)
to melt
heat = 1000g * 33 J/g
To calculate the amount of heat energy required to melt a 1 kg iron ingot initially at 20 °C, you can follow these steps:
Step 1: Convert the mass of your iron ingot to grams.
1 kg = 1000 g
Step 2: Find the temperature change from the initial temperature to the melting point of iron.
The melting point of iron is about 1535 °C.
Temperature change = final temperature - initial temperature
= 1535 °C - 20 °C
= 1515 °C
Note: We are converting the temperature to Celsius because the specific heat capacity and the heat of fusion are usually given in degrees Celsius.
Step 3: Calculate the energy required to raise the temperature of the iron ingot from its initial temperature to the melting point.
Heat energy (Q1) = mass × specific heat capacity × temperature change
The specific heat capacity of iron is about 0.45 J/g°C.
Q1 = 1000 g × 0.45 J/g°C × 1515 °C
Step 4: Calculate the energy required for the phase change (from solid to liquid) at the melting point.
Heat energy (Q2) = mass × heat of fusion
The heat of fusion for iron is given as 33.0 J/g.
Q2 = 1000 g × 33.0 J/g
Step 5: Calculate the total heat energy required.
Total heat energy = Q1 + Q2
Total heat energy = Q1 + Q2 = (1000 g × 0.45 J/g°C × 1515 °C) + (1000 g × 33.0 J/g)
By substituting the values into the equation, you can calculate the total heat energy required to melt the 1 kg iron ingot initially at 20 °C.
To calculate the amount of heat energy required to melt a 1kg iron ingot initially at 20°C, we need to use the formula:
Q = m * Hf
Where:
Q = amount of heat energy required (in Joules)
m = mass of the substance (in kg)
Hf = heat of fusion (in J/g)
First, let's convert the mass from grams to kilograms:
Mass of the iron ingot = 1 kg
Now, we can calculate the amount of heat energy required:
Q = 1 kg * Hf
Given that the heat of fusion for iron (Fe) is 33.0 J/g, we need to convert it from grams to kilograms:
Hf = 33.0 J/g * (1 kg / 1000 g)
Hf = 33.0 J/1000
Hence, the amount of heat energy required to melt a 1kg iron ingot initially at 20°C is:
Q = 1 kg * (33.0 J/1000)
Q = 0.033 J