na2co3(s)-h2o(l)2na+(aq)+co32-(aq)
Indicate your specific subject in the "School Subject" box, so those with expertise in the area will respond to the question.
What is your question?
The equation you provided represents the dissolution of sodium carbonate (Na2CO3) in water (H2O), resulting in the formation of sodium ions (Na+) and carbonate ions (CO32-). When Na2CO3 is added to water, it dissociates into its component ions.
To understand this chemical reaction, it is important to know that substances with ionic bonds (like sodium carbonate) can dissociate into their constituent ions when they come in contact with a polar solvent like water. In this case, sodium carbonate breaks down into two sodium ions (Na+) and one carbonate ion (CO32-).
The chemical equation you provided shows the balanced molecular equation for this reaction, indicating the states of matter for each species involved. "(s)" represents a solid, "(l)" represents a liquid, and "(aq)" represents an aqueous solution (dissolved in water).
So, when solid sodium carbonate (Na2CO3) is added to water (H2O), it dissolves, and the resulting solution contains sodium ions (Na+) and carbonate ions (CO32-).
To write the dissociation equation for this reaction, you would break down the solid compound into its constituent ions:
Na2CO3(s) --> 2Na+(aq) + CO32-(aq)
This equation shows that one formula unit of sodium carbonate dissociates into two sodium ions and one carbonate ion in aqueous solution.