Two resistors 3ohms and 6ohms are connected in parallel across a 6V battery, what is the current flow through the 3ohms resistors? Just the formula please.

You're just posted four physics questions under four different names.

Please use the same name for your posts.

I will next time but I really need help with these questions, any help would be appreciated.

I = E/R

Thank you!

To find the current flow through the 3-ohm resistor, you can use Ohm's Law, which states that the current (I) flowing through a resistor is equal to the voltage (V) across the resistor divided by the resistance (R) of the resistor.

The formula for Ohm's Law is:

I = V / R

In this case, the voltage (V) is 6V, and the resistance (R) is 3 ohms. Plugging these values into the formula, we get:

I = 6V / 3Ω

Simplifying the equation, we find:

I = 2A

Therefore, the current flowing through the 3-ohm resistor is 2 Amps.