sample of 1.00g of BaSO4 and a similar sample of 1.00g of CaSO4 were added to water at 25 Celsius to give 1L of solution. Calc. the concentration of Ba2+, Ca2+, and SO4^2- ions present in the solution?

What Ksp values are you using for BaSO4 and CaSO4?

It doesn't give anything else except what i wrote

Right, however, look in the tables in your text (usually in the back in the appendix) and you will find Ksp (solubility products) listed. Those are the numbers I need. Why can't I look them up? I can but tables don't agree and I want to use the same numbers you must use.

i was given the same problem...my text gives the Ksp of BaSO4= 1.1x10^-10. but not the Ksp of CaSO4

Ksp: BaSO4: 1.1*10^-10

CaSO4: can't find it

OK. I will assume the Ksp for CaSO4 is about 1E-4. The values I can find on the web aren't quite that but it makes the problem a little easier. Since you can't find it in your tables, I assume the problem is saying that 1.00 g CaSO4 is soluble in 1 L solution. If that is not a good assumption this won't be the right way to work the problem.

(CaSO4) = 1.00/molar mass CaSO4 = about 0.00734M
.........CaSO4 --> Ca^2+ + SO4^2-
.........solid....0.00734..0.00734
That gives the Ca^2+ and SO4^2-.

Then BaSO4 --> Ba^2+ + SO4^2-
I....solid.....0........0
C....solid.....x........x
E....solid.....x........x

Ksp BaSO4 = (Ba^2+)(SO4^2-)
(Ba^2+) = x from BaSO4
(SO4^2-) = x from BaSO4 and 0.00734 from CaSO4
Plug into Ksp for BaSO4 and solve for x = (Ba^2+).

To determine the concentration of Ba2+, Ca2+, and SO4^2- ions in the solution, we need to know the stoichiometry of the dissolution reaction for both BaSO4 and CaSO4. Let's start by writing the balanced chemical equations for the dissolution of each compound:

1. BaSO4 (s) → Ba2+ (aq) + SO4^2- (aq)
2. CaSO4 (s) → Ca2+ (aq) + SO4^2- (aq)

From the equations, we can see that one mole of BaSO4 will produce one mole of Ba2+ ions and one mole of SO4^2- ions, and the same applies to CaSO4.

Given that we have 1.00g of each compound, we need to convert these masses to moles using their molar masses. The molar mass of BaSO4 is approximately 233.4 g/mol, and the molar mass of CaSO4 is about 136.2 g/mol.

For BaSO4:
Moles of BaSO4 = (mass of BaSO4) / (molar mass of BaSO4) = 1.00g / 233.4 g/mol

For CaSO4:
Moles of CaSO4 = (mass of CaSO4) / (molar mass of CaSO4) = 1.00g / 136.2 g/mol

Since both compounds are dissolved in the same solution to give 1L, the concentration of each ion is equal to the number of moles divided by the volume in liters (i.e., 1L).

Concentration of Ba2+ = Moles of Ba2+ / Volume (in L)
Concentration of Ca2+ = Moles of Ca2+ / Volume (in L)
Concentration of SO4^2- = Moles of SO4^2- / Volume (in L)

Plug in the values and calculate the concentrations for each ion using the moles obtained previously.