two ice skaters initially at rest push each other.if one skater whose mass is 60kg has a velocity of 2m/s.find the velocity of other skater whose mass is 40kg
60x2=40xV
so
(60x2)/40 = 3m/s
60×2=40×V
So,
(60×20)/-40=-3M/S
Therefore v=-3M/S
No
To find the velocity of the other skater, we can use the principle of conservation of momentum. According to this principle, the total momentum before and after the interaction must remain the same.
The momentum of an object is given by the product of its mass and velocity. Mathematically, momentum (p) is represented as:
p = m * v
Where:
p = momentum
m = mass
v = velocity
In this scenario, we can set up the equation based on the principle of conservation of momentum:
Total initial momentum = Total final momentum
Initial momentum is zero, as the skaters are initially at rest. So, we have:
0 = (mass1 * velocity1) + (mass2 * velocity2)
Here, mass1 = 60 kg, velocity1 = 2 m/s, and mass2 = 40 kg (the mass of the other skater). We need to solve for velocity2 (the velocity of the other skater).
Plugging in the known values, we get:
0 = (60 kg * 2 m/s) + (40 kg * velocity2)
Simplifying the equation:
0 = 120 kg·m/s + 40 kg·m/s·velocity2
To solve for velocity2, let's isolate it:
0 - 120 kg·m/s = 40 kg·m/s·velocity2
-120 kg·m/s = 40 kg·m/s·velocity2
Dividing both sides by 40 kg·m/s, we find:
-3 m/s = velocity2
Therefore, the velocity of the other skater, whose mass is 40 kg, is -3 m/s. The negative sign indicates that the skater is moving in the opposite direction of the first skater.