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A 5.00 kg stone is thrown upward at 7.50 m/s at an angle of 51.0 degrees above the horizontal from the upper edge of a cliff, and it hits the ground 1.50 s later with no air drag. Find the magnitude of its velocity vector just as it reaches the ground.

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  1. Your school SUBJECT is probably physics.

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    Ms. Sue
  2. The horizontal speed does not change. It remains at

    7.5 cos51° = 4.72 m/s

    The vertical speed is given by v = Vo -9.8t, so it ends up at

    7.5 sin51° - 9.8*1.5 = -8.87 m/s

    So, the final speed is √(4.72^2 + 8.87^2) = 10.05 m/s

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  3. A car traveling 88 km/h is 110 m behind a truck traveling 75 km/h. how long will it take the car to reach the truck?

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