How do I graph a slope of 2/3 passing through the point of (-3,-4). Please help.
I was given this answer, but I am unsure if it is correct
**Since the slope is 2/3, go right up 3 and up 2 and plot another point.
start at (-3,-4) and mark it
since slope = rise/run = 2/3
the rise is 2 and the run is 3
so from the point (-3,-4) go to the right 3 (run of 3),
then go up 2 (rise of 2)
mark this new point, join with a line and you are done
Easy, eh ??
To graph a line with a given slope passing through a specific point, you can follow these steps:
1. Start by plotting the given point on an x-y coordinate plane. In this case, the point is (-3, -4). Locate -3 on the x-axis and -4 on the y-axis, then plot the point where these two values intersect.
2. Use the given slope of 2/3 to determine the next point on the line. Remember that slope represents the ratio of the change in y-values (vertical) to the change in x-values (horizontal).
In this case, the slope is 2/3, which means for every 3 units you move to the right (horizontally), you should move up 2 units (vertically).
3. Starting from the plotted point, move 3 units to the right horizontally. You can do this by counting 3 units to the right from the x-coordinate of the given point (-3).
4. Then, move up 2 units vertically from the point you obtained in the previous step. You can accomplish this by counting 2 units upward from the y-coordinate of the given point (-4).
5. Plot the new point at the coordinates you determined in steps 3 and 4. This new point will lie on the line with the given slope passing through the original point (-3, -4).
6. Finally, draw a straight line passing through the two plotted points. This line represents the graph of the given slope (2/3) passing through the point (-3, -4).
If you follow these steps correctly, you will be able to graph the line accurately.