A rowing team rowed an average of

17.2
miles per hour with the current and
10.4
miles per hour against the current. Determine the team's rowing speed in still water and the speed of the current
I need help fast. anyone?

speed = s

current = c

s + c = 17.2
s - c = 10.4
------------ add
2 s = 27.6
etc.

To determine the team's rowing speed in still water and the speed of the current, you can use the concept of relative motion. Let's call the rowing speed in still water as "s" and the speed of the current as "c".

When rowing with the current, the effective speed is the sum of the rowing speed in still water and the speed of the current. So, the effective speed with the current is s + c, which is 17.2 miles per hour.

When rowing against the current, the effective speed is the difference between the rowing speed in still water and the speed of the current. So, the effective speed against the current is s - c, which is 10.4 miles per hour.

Now we have two equations:
s + c = 17.2 ----(1)
s - c = 10.4 ----(2)

To solve these equations, you can use the method of addition or substitution. Let's use the method of addition:

Adding equation (1) and equation (2), we get:
2s = 27.6

Dividing both sides by 2, we find:
s = 13.8

Now, substitute the value of s into either equation (1) or equation (2) to find the value of c. Let's use equation (1):
13.8 + c = 17.2

Subtracting 13.8 from both sides, we get:
c = 17.2 - 13.8
c = 3.4

Therefore, the team's rowing speed in still water (s) is 13.8 miles per hour and the speed of the current (c) is 3.4 miles per hour.