When a pencil cell is released from a certain point on a inclined board,it travels a distance of 35cm on floor A before it comes to rest.when the same pencil cell is released from the same point on the same inclined board,it travels a distance of 20 cm on floor B before coming to rest.which floor A,B offers greater friction?give reason for your answer.
less distance ---> more friction, more retarding force
To determine which floor, A or B, offers greater friction, we need to consider the distances traveled by the pencil cell on each floor.
We know that the pencil cell starts from the same point on the inclined board and comes to rest on both floors. The distance traveled on floor A is 35 cm and on floor B it is 20 cm.
The amount of friction experienced by an object depends on the coefficient of friction and the normal force. The normal force is the force exerted by a surface perpendicular to the object's motion.
Assuming the angle of the inclined board is the same for both floors, the normal force acting on the pencil cell will also be the same for both floors because it depends on the weight of the pencil cell and the angle of the incline.
Since the normal force is the same, the only factor that can affect the distance traveled is the coefficient of friction. The coefficient of friction is a measure of how rough or smooth the surface is. A higher value of the coefficient of friction means more friction.
To determine which floor offers greater friction, we compare the distances traveled by the pencil cell. The floor where the pencil cell travels a shorter distance before coming to rest indicates greater friction.
In this case, the pencil cell travels a shorter distance (20 cm) on floor B before coming to rest, compared to floor A where it travels a longer distance (35 cm) before coming to rest. This means that floor B offers greater friction.
Hence, floor B offers greater friction than floor A.