The length of rectangle is 120% that of the breadth. The perimeter is 88m. Find the area of the rectangle?

2(w+1.2w) = 88

4.4w = 88
w = 20
so, area = 20(1.2*20) = 480

breadth --- x

length ---- 1.2x

2(x+1.2x) = 88
x+1.2x = 44
2.2x = 44
x = 20

area = x(1.2)x
= 1.2(20^2) = 480 m^2

To find the area of the rectangle, we need to know the length and breadth of the rectangle. Let's start by assigning variables:

Let's assume the breadth of the rectangle as 'x' meters.

According to the given information, the length of the rectangle is 120% of the breadth.

To find the length, we can use the formula: length = 120% of x = (120/100) * x = 1.2 * x

Now we can calculate the perimeter of the rectangle using the given formula: perimeter = 2(length + breadth).

Given that the perimeter is 88m, we can substitute the values:

88 = 2(1.2 * x + x)
44 = 2.2 * x
x = 44 / 2.2
x = 20

Now we know that the breadth of the rectangle is 20m. We can calculate the length using the formula: length = 1.2 * x = 1.2 * 20 = 24m.

Finally, we can find the area of the rectangle using the formula: area = length * breadth = 24 * 20 = 480 square meters.

Therefore, the area of the rectangle is 480 square meters.