sum ((√(n-1))-(√(n-1)))/n, as n=1
To find the value of the given expression, let's break it down:
The expression is:
((√(n-1)) - (√(n-1))) / n
Now, let's substitute n = 1 into the expression:
((√(1-1)) - (√(1-1))) / 1
((√0) - (√0)) / 1
Since the square root of 0 (√0) is 0, we can simplify further:
(0 - 0) / 1
0 / 1
The result of the expression when n = 1 is 0.