1. 48 KNO3+ _ C 12 H22O11-„³ ? CO2+ _ N2+ _ K2CO3+ _ H2O
a. 12
b. 24 s
c. 36
d. 48
The reaction is
48 KNO3 + 5 C12H22O11 --> 24 K2CO3 + 36 CO2 + 55 H2O + 24 N2
So the answer is C =36
2. 6 KNO3+ _ S + ? H2O„³ _ H2SO4+ _ N2+ _ K2SO4
a. 2
b. 4
c. 6
d. 8
The balanced reaction is
6KNO3 + 5S + 2H2O „³ 3 H2SO4 + 3N2 + 2K2SO4
The answer to H2O is 2
3. 42 KMnO4+ _ C3H5(OH)3 „³CO2+ _ Mn2O3+ _ K2CO3+ _ H2O
a. 5
b. 15
c. 18
d. 7
The reaction is
14 KMnO4 + 4 C3H5(OH)3 --> 7 K2CO3 + 7 Mn2O3 + 5 CO2 + 16 H2O
The answer for CO2 is 5 X 3 =15 (answer B)
4. 42 KMnO4 + ? C3H5(OH)3--„³ _ CO2+ _ Mn2O3+ _ K2CO3+ _ H2O
a. 6
b. 7
c. 8
d. 12
The reaction is
14 KMnO4 + 4 C3H5(OH)3 --> 7 K2CO3 + 7 Mn2O3 + 5 CO2 + 16 H2O
answer is 3X4 =12 (answer D)
5. 6 KNO3+ _ S + _ H2O ? H2SO4+ _ N2+ _ K2SO4
a. 2
b. 4
c. 6
d. 12
The balanced reaction is
6KNO3 + 5S + 2H2O „³ 3 H2SO4 + 3N2 + 2K2SO4
so for 6 KNO3 the answer to H2SO3 is 2 (answer A)
6. 42 KMnO4 + ? C3H5(OH)3 _ CO2+ _ Mn2O3+ _ K2CO3+ _ H2O
a. 6
b. 7
c. 12
d. 42
The balanced reaction is
14 KMnO4 + 4 C3H5(OH)3 --> 7 K2CO3 + 7 Mn2O3 + 5 CO2 + 16 H2O
answer is 3X4 =12 (answer C)
7. 12 C3H5(OH)3 + ? KMnO4„³ _ CO2+ _ Mn2O3+ _ K2CO3+ _ H2O
a. 6
b. 12
c. 8
d. 42
The balanced reaction is
14 KMnO4 + 4 C3H5(OH)3 --> 7 K2CO3 + 7 Mn2O3 + 5 CO2 + 16 H2O
answer is 14 X 3 = 42 (answer D)
8. 5 S + _ KNO3+ _ H2O _ H2SO4 + ? N2+ _ K2SO4
a. 3
b. 6
c. 10
d. 15
The balanced reaction is
6KNO3 + 5S + 2H2O „³ 3 K2SO4 + 3N2 + 2H2SO4
the coefficient for N2 is 3 (answer A)
9. 5 C12H22O11 + ? KNO3 _ CO2+ _ N2+ _ K2CO3+ _ H2O
a. 5
b. 15
c. 24
d. 48
The balanced reaction is
96 KNO3 + 10 C12H22O11 --> 48 K2CO3 + 72 CO2 + 110 H2O + 48 N2
So the answer for KNO3 is 48 (answer D)
10. 48 KNO3 + ? C12H22O11 _ CO2+ _ N2+ _ K2CO3+ _ H2O
a. 5
b. 7
c. 6
d. 12
The balanced reaction is
48 KNO3 + 5 C12H22O11 --> 24 K2CO3 + 36 CO2 + 55 H2O + 24 N2
So the answer for the C12H22O11 is 5 (answer A)
I didn't see any different answers. I did see some typos on your part and they are in this post, also. And some of the characters can't be read by my computer so I must guess the location of the arrow. Finally, I'm not sure what the question for each problem is but here goes.
1. 48 KNO3+ _ C 12 H22O11-„³ ? CO2+ _ N2+ _ K2CO3+ _ H2O
a. 12
b. 24 s what't the s?
c. 36
d. 48
The reaction is
48 KNO3 + 5 C12H22O11 --> 24 K2CO3 + 36 CO2 + 55 H2O + 24 N2
So the answer is C =36 right. I think this makes 4 times I have anwered this question.
2. 6 KNO3+ _ S + ? H2O„³ _ H2SO4+ _ N2+ _ K2SO4
a. 2
b. 4
c. 6
d. 8
The balanced reaction is
6KNO3 + 5S + 2H2O „³ I don't recognize this symbol. Probably an arrow 3 H2SO4 + 3N2 + 2K2SO4 I think you have interchanged these. I believe it is 3K2SO4 and 2H2SO4.
The answer to H2O is 2 right
3. 42 KMnO4+ _ C3H5(OH)3 „³CO2+ _ Mn2O3+ _ K2CO3+ _ H2O
a. 5
b. 15
c. 18
d. 7
The reaction is
14 KMnO4 + 4 C3H5(OH)3 --> 7 K2CO3 + 7 Mn2O3 + 5 CO2 + 16 H2O
The answer for CO2 is 5 X 3 =15 (answer B)
I don't understand where the 42 comes in and then you changed it to 14 for KMnO4. As far as I can tell, the 14, along with all of your other coefficients, balances the equation, both for atoms and change of electrons. So I suppose you have simply made 5 CO2 X (42/14)= 5 x 3 = 15. If this isn't correct, let me know.
4. 42 KMnO4 + ? C3H5(OH)3--„³ _ CO2+ _ Mn2O3+ _ K2CO3+ _ H2O
a. 6
b. 7
c. 8
d. 12
The reaction is
14 KMnO4 + 4 C3H5(OH)3 --> 7 K2CO3 + 7 Mn2O3 + 5 CO2 + 16 H2O
answer is 3X4 =12 (answer D)
See my comment above. If that is true, then 12 is right fo this one.
5. 6 KNO3+ _ S + _ H2O ? H2SO4+ _ N2+ _ K2SO4
a. 2
b. 4
c. 6
d. 12
The balanced reaction is
6KNO3 + 5S + 2H2O „³ 3 H2SO4 + 3N2 + 2K2SO4 Shouldn't this be 3K2SO4 and 2H2SO4. I think you interchanged them.
so for 6 KNO3 the answer to H2SO3 (should be H2SO4) is 2 (answer A)
6. 42 KMnO4 + ? C3H5(OH)3 _ CO2+ _ Mn2O3+ _ K2CO3+ _ H2O
a. 6
b. 7
c. 12
d. 42
The balanced reaction is
14 KMnO4 + 4 C3H5(OH)3 --> 7 K2CO3 + 7 Mn2O3 + 5 CO2 + 16 H2O
answer is 3X4 =12 (answer C) Ok but see my previous comments.Is this the same problem as 4?
7. 12 C3H5(OH)3 + ? KMnO4„³ _ CO2+ _ Mn2O3+ _ K2CO3+ _ H2O
a. 6
b. 12
c. 8
d. 42
The balanced reaction is
14 KMnO4 + 4 C3H5(OH)3 --> 7 K2CO3 + 7 Mn2O3 + 5 CO2 + 16 H2O
answer is 14 X 3 = 42 (answer D) OK but see my previous comment.
8. 5 S + _ KNO3+ _ H2O _ H2SO4 + ? N2+ _ K2SO4
a. 3
b. 6
c. 10
d. 15
The balanced reaction is
6KNO3 + 5S + 2H2O „³ 3 K2SO4 + 3N2 + 2H2SO4
the coefficient for N2 is 3 (answer A) ok.
9. 5 C12H22O11 + ? KNO3 _ CO2+ _ N2+ _ K2CO3+ _ H2O
a. 5
b. 15
c. 24
d. 48
The balanced reaction is
96 KNO3 + 10 C12H22O11 --> 48 K2CO3 + 72 CO2 + 110 H2O + 48 N2
The balanced reaction is half of each of the coefficients you show. 48 is correct for KNO3.
So the answer for KNO3 is 48 (answer D)
10. 48 KNO3 + ? C12H22O11 _ CO2+ _ N2+ _ K2CO3+ _ H2O
a. 5
b. 7
c. 6
d. 12
The balanced reaction is
48 KNO3 + 5 C12H22O11 --> 24 K2CO3 + 36 CO2 + 55 H2O + 24 N2
So the answer for the C12H22O11 is 5 (answer A) ok
thank you so much
KMn3 + C3H5(OH)3 - K2CO3 + Mn2O3 + CO2 + H2O
You're welcome! I'm glad I could help. Just a small correction, the balanced reaction you provided is not correct. The correct balanced reaction for KMnO4 + C3H5(OH)3 is:
14 KMnO4 + 4 C3H5(OH)3 --> 7 Mn2O3 + 6 CO2 + 8 K2CO3 + 16 H2O
So the answer to the question is actually:
c. 6
I'm sorry, but I'm unable to understand the question you're asking. Can you please rephrase or provide more information?
You're welcome! I'm glad I could help. Just a small correction: the balanced equation for KMnO4 + C3H5(OH)3 is actually:
14 KMnO4 + 4 C3H5(OH)3 → 7 K2CO3 + 7 Mn2O3 + 5 CO2 + 16 H2O
This means that for every 14 KMnO4, you will need 4 C3H5(OH)3 to balance the equation. Similarly, for every 5 CO2 produced, there will be 5 × 3 = 15 molecules of C3H5(OH)3 consumed. So, the answer to the question "5 C12H22O11 + ? KNO3 → CO2 + N2 + K2CO3 + H2O" is D. 48, as every 48 KNO3 is required to balance the equation.
If you have any more questions, feel free to ask!