Hello,
Please help me with this question!
Which dilution would turn 10% (by mass) HCl solution into 0.100 M HCl solution?
Density of 10% HCL = 1.08 g ml^-1
lets find the Molarity of the 10 percent solution.
assume 1000g of solution, or 100gHCL, 900g H2O. moles HCl= 100/36.5=2.80 moles
now this solution has a density of 1.08, so the volume is 1000g/1.08g/ml= .917 liters
Molarity= 2.80/.917 =3.05M
you want to dilute it 3.05/.1=30.5times
which means one part original, 29.5 parts water.
What is one part? it is the volume desired of the .1M, divided by 30.5
twenty-nine point five parts is that one part multiplied by 29.5
To find the dilution required to turn a 10% HCl solution into a 0.100 M HCl solution, we need to understand the relationship between concentration, volume, and amount of solute.
First, let's calculate the amount of solute present in the 10% HCl solution.
Given:
Mass percent = 10%
Density = 1.08 g mL^-1
Assume we have 100 mL of the 10% HCl solution. Since the density is 1.08 g/mL, the mass of the solution is:
Mass = Volume x Density = 100 mL x 1.08 g/mL = 108 g
The mass percent gives us the amount of solute in 100 g of the solution. So, in 108 g of solution, the amount of solute (HCl) is:
Amount of HCl = (10/100) x 108 g = 10.8 g
Next, we need to calculate the volume of the required 0.100 M HCl solution.
Molarity (M) is defined as the amount of solute (in moles) divided by the volume of the solution (in liters).
Molarity (M) = Moles of solute / Volume of solution (in L)
To find the moles of solute required for the new concentration, we'll use the equation:
Moles = Molarity x Volume (in L)
Rearranging the equation, we get:
Volume = Moles / Molarity
We want a final volume of 1 liter (1000 mL) of 0.100 M HCl solution. So we substitute the values:
Volume = (10.8 g / 36.461 g/mol) / 0.100 mol/L = 29.8 mL
Therefore, to prepare 1 liter of 0.100 M HCl solution, we need to dilute 29.8 mL of the 10% HCl solution to 1000 mL (or 1 liter) by adding the appropriate amount of solvent (water).
In summary, the required dilution to turn a 10% (by mass) HCl solution into a 0.100 M HCl solution is to take 29.8 mL of the 10% HCl solution and dilute it to 1000 mL (or 1 liter).