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a force F is applied in horizontal to a 10kg block. the block moves at a constant speed 2m/s across a horizontal surface. the coefficient of kinetic friction between the block and the surface is 0.5. the work done by the force F in 1.5 minutes is?

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kristen

  1. work=force*distance
    = 10*g*.5*2*1.5min*60sec/min

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    bobpursley

  2. 9000

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    Anonymous

  4. fn*m(coeffient of friction) = f(friction)
    100*.5=50

    Make velocity graph, convert 1.5min to seconds (60*1.5=90sec)
    since constant, no acceleration
    graph should look like rectangle v=2 on y axis t=90 on x axis
    multiply like rectangle (2*90=180)
    180 meters is the result
    W=F*D
    W=50 * 180
    W=9000J
    hope this helps <3

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    dayna

  5. ggez

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    Anonymous

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