what are the excluded values?
y+5/y^2+4y-32
To find the excluded values for the expression (y + 5) / (y^2 + 4y - 32), we need to identify any values of y that would make the denominator equal to zero. This is because division by zero is undefined.
In this case, the denominator is a quadratic expression, y^2 + 4y - 32. To find the values of y for which the denominator equals zero, we can set the equation equal to zero and solve for y.
y^2 + 4y - 32 = 0
To solve this quadratic equation, you can use factoring, completing the square, or the quadratic formula. In this case, let's use factoring:
(y + 8)(y - 4) = 0
Setting each factor to zero, we have:
y + 8 = 0 or y - 4 = 0
Solving for y in each equation, we find:
y = -8 or y = 4
Thus, the excluded values for the expression (y + 5) / (y^2 + 4y - 32) are y = -8 and y = 4, since plugging in these values of y would result in a division by zero.
the answer choices for this question is.
y = -5 and 4
y = 5 and 32
y = 4 and -8
none of the above
again, you should type it as
(y+5)/(x^2 + 4y - 32) , the way you have it, the only division is 5/y^2
= (y+5)/((y+8)(y-4))
so which values would make the denominator zero ?