factorize completely X^2 + 2X^2 - 15X / 2X^2 - 18
x^3+2x^2-15x = x(x+5)(x-3)
2x^2-18 = 2(x-3)(x+3)
Now just cancel the (x-3) top and bottom
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To factorize the given expression, let's first simplify it:
X^2 + 2X^2 - 15X = 3X^2 - 15X
Now let's simplify the denominator:
2X^2 - 18 = 2(X^2 - 9) = 2(X - 3)(X + 3)
Now we can rewrite the expression as:
(3X^2 - 15X) / (2X^2 - 18) = (3X(X - 5)) / (2(X - 3)(X + 3))
So the fully factorized form of the expression is:
(3X(X - 5)) / (2(X - 3)(X + 3))