How much heat must be added to 128.7 g of ice at 0 degrees Celsius to melt the ice completely?
Answer = _____calories
128.7*80=10296
To find out how much heat is required to melt the ice completely, we can use the equation Q = m * ΔHf, where Q is the heat energy, m is the mass of the substance, and ΔHf is the heat of fusion.
In this case, the mass of the ice is given as 128.7 g. The heat of fusion for ice is approximately 79.7 calories/gram.
Now, we can substitute these values into the equation:
Q = 128.7 g * 79.7 cal/g = 10266.99 calories
Therefore, approximately 10,267 calories (or 10,267.16 calories to be more precise) must be added to completely melt the ice.