physics

A body starts with an initial velocity of 10m/s and moves along a straight line with a constant acceleration. When the velocity of the particle becomes 50 m/s the acceleration is reversed in direction without changing magnitude. Find the velocity of the particle when it reaches the starting point.

asked by karan
  1. position when it hits 50m/s:

    vf^2=vi^2+2ad
    50^2=10^2+2*a*d solve for a*d.

    Now, the reverse trip:
    vf^2=50^2 -2ad put the above in, and viola,

    vf^2=50^2-50^2+10^2=10^2
    vf=10
    Think that out in your mind.

    posted by bobpursley
  2. -70m/s^2

    posted by Krishiv and Prateek

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