Which of the following solutions do they have the maximum osmotic pressure :
1) 0.1 m ( molal conc.) glucose
2) 0.1 m sucrose
3) 0.5 m glucose
4) 0.2 m sucrose
and why ?
pi = iMRT
i is 1 for the four listed so it all depends upon M. Which M gives the largest pi?
IT'S PLANE SIMPLE! (10/10 points)
Calculate the planar packing density (fractional area occupied by atoms) on the (110) plane of nickel at 300K.
0.5549 - correct
\[0.5549\]
Calculate the linear packing density (atoms/cm) for the [100] direction in nickel at 300K.
2.837*10^7 - correct
\[2.837\cdot 10^{7}\]
To determine which solution has the maximum osmotic pressure, we need to understand two important factors: concentration and molecular weight. The osmotic pressure of a solution depends directly on the concentration of solute particles and the molecular weight of these particles.
In this case, we are comparing solutions of glucose and sucrose with different concentrations. To find the osmotic pressure, we can use the formula:
Osmotic pressure (π) = Molarity (M) × Gas constant (R) × Temperature (T)
However, in this problem, we are given molal concentration (m), which is slightly different from molarity. Molality (m) is calculated by dividing the moles of solute by the mass of the solvent in kilograms.
First, let's calculate the osmotic pressure for each of the given solutions:
1) 0.1 m (molal conc.) glucose:
To find the osmotic pressure, we need to know the molecular weight of glucose (C6H12O6), which is 180 g/mol. But the molarity is given as 0.1 m, which means 0.1 mol of glucose is present in 1000 grams of water (assuming water as the solvent). Therefore, the osmotic pressure can be calculated using the formula:
π = (0.1 mol / 1 kg) × (180 g/mol) × (R) × (T)
2) 0.1 m sucrose:
Similar to the glucose solution, we need the molecular weight of sucrose (C12H22O11), which is 342 g/mol. With the given concentration of 0.1 m, we can calculate the osmotic pressure as:
π = (0.1 mol / 1 kg) × (342 g/mol) × (R) × (T)
3) 0.5 m glucose:
Using the same approach, we can calculate the osmotic pressure for this solution:
π = (0.5 mol / 1 kg) × (180 g/mol) × (R) × (T)
4) 0.2 m sucrose:
Again, we can calculate the osmotic pressure using the given concentration and molecular weight of sucrose:
π = (0.2 mol / 1 kg) × (342 g/mol) × (R) × (T)
After calculating the osmotic pressures for all solutions, we can compare the values to determine which has the maximum osmotic pressure. The solution with the highest osmotic pressure will contain the solute with greater concentration and/or higher molecular weight.