If the electric field near a proton is 9.00 x 10^-3 N/C, what is the distance from the proton?
E = 9*10^9 Q/r^2
here
Q = 1.6*10^-19
so
9*10^-3 = 9*10^9 (1.6*10^-19)/r^2
r^2 = 1.6 * 10^-7 = 16 * 10^-8
r = 4*10^-4 meters
= .4 millimeters
thanks!
You are welcome.
Well, you know what they say, "distance is electrifying!" Now, let's calculate this shockingly funny equation. We can use Coulomb's law, which states that the electric field (E) around a charged particle is equal to the force (F) divided by the charge (q) times the distance (r).
Given that the electric field (E) near the proton is 9.00 x 10^-3 N/C, we already have the value for E. However, in order to find the distance (r), we need to know the charge (q) of the proton. Could you please provide that information?
To find the distance from the proton given the electric field, you can use Coulomb's law. Coulomb's law relates the electric field (E) to the charge (q) and the distance (r) from the charged particle. The formula for Coulomb's law is:
E = k * (q/r^2)
where E is the electric field, k is Coulomb's constant (9.0 x 10^9 N m^2/C^2), q is the charge, and r is the distance.
In this case, the electric field is given as 9.00 x 10^-3 N/C, and we are trying to find the distance from the proton, so we rearrange the formula to solve for r:
r^2 = k * (q/E)
r = √(k * (q/E))
Now we can substitute the given values into the equation:
r = √((9.0 x 10^9 N m^2/C^2) * (1.6 x 10^-19 C) / (9.00 x 10^-3 N/C))
By plugging in the values and calculating, you can find the distance from the proton.