A staging that weighs 140 N support two painters, one 500 N and the other 520 N. The reading in the left scale is fl = 740 N. what is the reading Fr in the right hand scale
ive added the weight of the 2 painters, then subtracted the weight of the staging?
never mind I'm an idiot
The scales should add to the weight of the two painters PLUS the weight of the staging.
740+Fright=140+500+520
To find the reading Fr on the right-hand scale, we can use the concept of equilibrium. In equilibrium, the sum of all forces acting on an object is equal to zero.
In this scenario, the staging is in equilibrium, which means the downward force exerted by the painters is balanced by the upward support force of the staging.
Given that the staging weighs 140 N and the combined weight of the two painters is (500 N + 520N) = 1020 N, the total downward force is 140 N + 1020 N = 1160 N.
Since the staging is in equilibrium, the upward support force must be equal to the total downward force. Therefore, the reading on the left-hand scale is equal to the downward force, which is 1160 N.
Now, we can find the reading on the right-hand scale (Fr) by subtracting the reading on the left scale (Fl) from the total weight of the painters (1020 N + 500 N + 520 N = 2040 N), which is:
Fr = Total weight of the painters - Fl
= 2040 N - 740 N
= 1300 N
Therefore, the reading on the right-hand scale, Fr, is 1300 N.