a 12 V battery is made of 36 cells each rates at 2V and 1.5 A for a given duty cycle. what is the line current and power that may be drawn from the battery?
Tnx :)
are the cells in series or in parallel?
Probably 6 cells in series to give 12 v, then 6 sets of those (36 cells total) in parallel.
I suspect that Steve has the diagram right.
Then each of the six branches can carry 1.5 amps
so 9 amps total
9*12 = 108 Watts
Interesting, went nameless :)
To calculate the line current and power that can be drawn from the battery, we need to use Ohm's Law and the power formula.
First, let's calculate the total voltage of the battery. We know that each cell has a voltage rating of 2V, and there are 36 cells in total. Therefore, the total voltage of the battery is:
Total voltage = 2V/cell * 36 cells = 72V
Now, let's find the line current using Ohm's Law. Ohm's Law states that the current (I) flowing through a circuit is equal to the voltage (V) divided by the resistance (R). In this case, the resistance would be the equivalent resistance of the load connected to the battery.
Since we don't know the resistance of the load, we cannot directly calculate the line current using the given information. However, we can calculate the power that can be drawn from the battery and use it to estimate the line current.
To calculate power, we use the formula:
Power (P) = Voltage (V) * Current (I)
In this case, we know the voltage (12V), but we don't have the current value. However, we are given the current rating for a given duty cycle. The duty cycle represents the fraction of time that the load draws the rated current. Assuming a 100% duty cycle, we can use the given current rating of 1.5A.
Therefore, the maximum power that can be drawn from the battery is:
Power = Voltage * Current = 12V * 1.5A = 18W
To estimate the line current, we can divide the power by the voltage:
Line current (I) = Power / Voltage = 18W / 72V = 0.25A (or 250mA)
So, the line current that may be drawn from the battery is approximately 0.25A (or 250mA), and the power that can be drawn is 18W.
Please note that these calculations assume ideal conditions and do not take into account any losses or inefficiencies in the system.